- 奇怪的函数1
const connect = s => p => connect(p(s)) const origin = 10 const task = req => req + 1 const output = res => { console.log(res) return res } connect(origin)(task)(task)(task)(task)(task)(output)
- Y组合子实现匿名递归
找规律?
const sum = num => (num > 0 ? num + sum(num - 1) : num) const sumR = sum => num => (num > 0 ? num + sum(sum)(num - 1) : num) console.log((f => f(f))(sum => num => num > 0 ? num + sum(sum)(num - 1) : num)(3)) // 6 console.log((f => f(f))(sum => num => num > 0 ? num + ((f => f(f))(sum))(num - 1) : num)(3)) // 6 console.log(sumR(sumR)(3))